In a solid if F = V = 5, then the number of edges in this shape is
(a) 6
(b) 4
(c) 8
(d) 2

Solution:

Given, F = V = 5

We have to find the number of edges.

Euler’s formula for any polyhedron is, F + V – E = 2

Where F stands for number of faces,

V for number of vertices

E for number of edges.

According to the question,

5 + 5 - E = 2

10 - E = 2

E = 10 - 2

E = 8

Therefore, the number of edges is 8.

✦ Try This: In a solid if F = V = 6, then the number of edges in this shape is (a) 6, (b) 4, (c) 10, (d) 2

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 10

NCERT Exemplar Class 8 Maths Chapter 6 Problem 8

In a solid if F = V = 5, then the number of edges in this shape is (a) 6, (b) 4, (c) 8, (d) 2

Summary:

In a solid if F = V = 5, then the number of edges in this shape is 8.

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