In a rectangular plot, 5 square flower beds of side (x + 2) metres each have been laid (see figure given below). Find the total cost of fencing the flower beds at the cost of ₹50 per 100 metres
Solution:
Given, a rectangular plot contains 5 square flower beds of side (x + 2) metres.
We have to find the total cost of fencing the flower beds at the cost of ₹50 per 100 metres.
Considering one square flower bed,
Side = x + 2
Perimeter of square = 4(side)
= 4(x + 2)
= 4x + 8 m
Cost of fencing 100 metres = ₹50
Cost of fencing 1 metre = 50/100
= ₹1/2
Cost of fencing (4x + 8) metres = 1/2 × (4x + 8)
Taking out 2 as common,
= 1/2 × [2(2x + 4)]
Cancelling out common term,
= 2x + 4
The cost of fencing one square flower bed = ₹2x + 4
Cost of fencing 5 square flower beds = 5(2x + 4)
= ₹10x + 20
Therefore, the total cost of fencing is ₹10x + 20.
✦ Try This: Find the perimeter of the figure given below:
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 12
NCERT Exemplar Class 7 Maths Chapter 10 Problem 82
In a rectangular plot, 5 square flower beds of side (x + 2) metres each have been laid (see figure given below). Find the total cost of fencing the flower beds at the cost of ₹50 per 100 metres
Summary:
In a rectangular plot, 5 square flower beds of side (x + 2) metres each have been laid (see figure given below). The total cost of fencing the flower beds at the cost of ₹50 per 100 metres is ₹(10x + 20)
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