In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000

Solution:

Let the initial count of the bacteria be 'P' = 506000, n = 2, R = 2.5%

The count of the bacteria after 2 hours is assumed as 'A' and calculated as follows:

A = P[1 + (R/100)]ⁿ

A = 506000[1 + (25/1000)]²

A = 506000[1 + (1/40)]²

A = 506000 × (41/40)²

A = 506000 × (41/40) × (41/40)

A = 506000 × (1681/1600)

A = 506000 × 1.050625

A = 531616(approx.)

☛ Check: NCERT Solutions for Class 8 Maths Chapter 8

Video Solution:

In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000

NCERT Solutions Class 8 Maths Chapter 8 Exercise 8.3 Question 11

Summary:

In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. The bacteria at the end of 2 hours is 531616 if the count was initially 5,06,000.

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