(i) Identify the terms and their factors in the following expressions. Show the terms and factors by tree diagrams
(a) x – 3   (b) 1 + x + x²    (c) y – y³
(d) 5xy² + 7x²y   (e) – ab + 2b² – 3a²
(ii) Identify terms and factors in the expressions given below:
(a) -4x + 5   (b) -4x + 5y   (c) 5y + 3y²   (d) xy + 2x²y²
(e) pq + q   (f) 1.2ab – 2.4b + 3.6a   (g) (3/4)x+1/4
(h) 0.1p² + 0.2q²

Solution:

(i)

(a) x - 3

Term = x, - 3 and Factor = x; -3

(b) 1 + x + x²

Term = 1, x, x² and Factor = 1, x, (x,x)

(c) y - y³

Term = y, - y³ and Factor = y, (-1, y, y, y)

(d) 5xy² + 7x²y

Term = 5xy², 7x²y and Factor = (5, x, y, y), (7, x, x, y)

(e) -ab + 2b² - 3a²

Term = -ab, 2b², -3a² and Factor = (-a, b), (2, b, b), (-1, 3, a, a)

(ii) Identification of terms and factors in the expressions given below:

Factors is defined as, numbers we can multiply together to get another number.

Sl.No.	Expression	Terms	Factors
(a)	– 4x + 5	-4x 5	-4, x 5
(b)	– 4x + 5y	-4x 5y	-4, x 5, y
(c)	5y + 3y2	5y 3y2	5, y 3, y, y
(d)	xy + 2x2y2	xy 2x2y2	x, y 2, x, x, y, y
(e)	pq + q	pq q	p, q q
(f)	1.2 ab – 2.4 b + 3.6 a	1.2ab -2.4b 3.6a	1.2, a, b - 1, 2.4, b 3.6, a
(g)	(3/4) x + 1/4	(3/4) x 1/4	3/4, x 1/4
(h)	0.1 p2 + 0.2 q2	0.1p2 0.2q2	0.1, p, p 0.2, q, q

☛ Check: NCERT Solutions for Class 7 Maths Chapter 12

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Video Solution:

(i) Identify the terms and their factors in the following expressions Show the terms and factors by tree diagrams.(a) x – 3 (b) 1 + x + x²  (c) y – y³ (d) 5xy² + 7x²y (e) – ab + 2b² – 3a² (ii) Identify terms and factors in the expressions given below: (a) -4x + 5 (b) -4x + 5y (c) 5y + 3y² (d) xy + 2x²y² (e) pq + q (f) 1.2ab – 2.4b + 3.6a (g) (3/4)x+1/4 (h) 0.1p² + 0.2q²

Maths NCERT Solutions Class 7 Chapter 12 Exercise 12.1 Question 2

Summary:

(i) Identifying the terms and their factors in the following expressions shown the terms and factors by tree diagrams is shown above in the solution.(a)  x – 3; Term = x, - 3 and Factor = x; -3 (b) 1 + x + x²; Term = 1, x, x² and Factor = 1, x, (x,x) (c) y – y³; Term = y, -y³ and Factor = y, (-y, -y, -y) (d) 5xy² + 7x²y; Term = 5xy², 7x²y and Factor = (5, x, y, y), (7, x, x, y) (e) – ab + 2b² – 3a²; Term = -ab, 2b², -3a² and Factor = (-a, b), (2, b, b), (-3, a, a)

(ii) Identification of terms and factors in the expressions given below: (a) -4x + 5; Terms = -4x and 5 and Factors = x and 5. (b) -4x + 5y; Terms = -4x and 5y ; Factors = -4, x and 5, y (c) 5y + 3y²; Terms = 5y and 3y² Factors 5,y and 3, y, y. (d) xy + 2x²y²; Terms = xy and 2x²y²; Factors= x, y and 2, x, x, y, y. (e) pq + q; Term = pq and q; Factor = p, q and q (f) 1.2ab – 2.4b + 3.6a; Term = 1.2ab, - 2.4b and 3.6a and Factor = 1.2, a, b, −2.4, b and 3.6, a. (g)  (3/4)x+1/4; Term = (3/4)x and 1/4 ; Factor = (3/4), x and 1/4 (h) 0.1p² + 0.2q²; Term = 0.1p² and 0.2q²;Factor = 0.1, p, p and 0.2, q, q.

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