A day full of math games & activities. Find one near you.

If x be any integer different from zero and m be any positive integer, then x^-m is equal to
(a) x^m
(b) -x^m
(c) 1/x^m
(d) -1/x^m

Solution:

The correct option is (c)

Using laws of indices, For any non-zero integer a, a^-m = 1/a^m

x^-m = 1/x^m

✦ Try This: Let y = 3^-2 then 9y is equal to (a) 0, (b) -1, (c) 1, (d) None of these

The correct option is (c)

Given, y = 3^-2, 9y = 9 × 3^-2 using laws of indices, For any non-zero integer a, a^-m = 1/a^m

⇒ 9y = 9 × (1/32) = 9 × (1/ 9) = 1

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 12

NCERT Exemplar Class 8 Maths Chapter 8 Problem 15

If x be any integer different from zero and m be any positive integer, then x^-m is equal to (a) x^m, (b) -x^m, (c) 1/x^m, (d) -1/x^m

Summary:

If x be any integer different from zero and m be any positive integer, then x^-m is equal to 1/ x^m

☛ Related Questions: