If x = 1/10 and y = -3/8 then evaluate x + y, x - y, x × y and x ÷ y.

Solution:

Given, x = 1/10 and y = -3/8

We have to find x + y, x - y, x × y and x ÷ y.

a) x + y = 1/10 + (-3/8)

On simplification,

x + y = [1(8) + (-3)(10)] / 10(8)

= (8 - 30)/80

= -22/80

= -11/40

Therefore, x + y = -11/22

b) x - y = 1/10 - (-3/8)

On simplification,

x - y = [1(8) - (-3)(10)] / 10(8)

= (8 - (-30))/80

= (8 + 30)/80

= 88/80

= 11/40

Therefore, x - y = 11/40

c) x × y = (1/10) × (-3/8)

= 1×(-3) / (10 × 8)

If the signs of the factors are different, the product is negative.

= -3/80

Therefore, x × y = -3/80

d) x ÷ y = (1/10) ÷ (-3/8)

Reciprocal of -3/8 = 1/(-3/8)

= -8/3

So, (1/10) ÷ (-8/3) = 1 × (-8) / 10 × 3

If the signs of the factors are different, the product is negative.

= -8/30

= -4/15

Therefore, x ÷ y = -4/15.

✦ Try This: If x = 3/4 and y = -5/3, then evaluate x + y, x - y, x × y and x ÷ y.

☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 9

NCERT Exemplar Class 7 Maths Chapter 8 Problem 85

If x = 1/10 and y = -3/8 then evaluate x + y, x - y, x × y and x ÷ y

Summary:

If x = 1/10 and y = -3/8 then, x + y = -11/22, x - y = 11/40, x × y = -3/80, x ÷ y = -4/15

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