If the common difference of an AP is 5, then what is a₁₈ - a₁₃ ?
a. 5
b. 20
c. 25
d. 30

Solution:

An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous term.

The nth term of an AP is

aₙ = a + (n - 1 )d.

a = first term

aₙ = nth term

d = common difference.

The common difference of AP , d = 5

a₁₈ -a₁₃ = a + 17d - (a + 12d)

a₁₈ -a₁₃ = a + 17d - a - 12d

a₁₈ -a₁₃ = 17d - 12d

a₁₈ -a₁₃ = 5d

a₁₈ -a₁₃ = 5(5)

a₁₈ -a₁₃ = 25.

Therefore, a₁₈ -a₁₃ = 25.

✦ Try This: The 6th term of an AP is 6 and the 16th term is 14. What is the 27th term

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 5

NCERT Exemplar Class 10 Maths Exercise 5.1 Problem 9

If the common difference of an AP is 5, then what is a₁₈ - a₁₃, a. 5, b. 20, c. 25, d. 30

Summary:

An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. If the common difference of an AP is 5, then a₁₈ - a₁₃ is 25

☛ Related Questions:

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