If the 3rd and the 9th terms of an AP are 4 and - 8 respectively, which term of this AP is zero?
Solution:
The formula for nth term of an AP is aₙ = a + (n - 1) d
Here, aₙ is the nth term, a is the first term, d is the common difference and n is the number of terms.
3rd term of the AP = 4
a₃ = a + (3 - 1)d = 4
a + 2d = 4 .... (1)
9th term of the AP = - 8
a₉ = a + (9 - 1)d = - 8
a + 8d = - 8 ....(2)
Solving (1) and (2) for a and d
a + 2d - (a + 8d) = 4 - (- 8)
- 6d = 12
d = - 2
Putting d = - 2 in equation (1)
a + 2 × (- 2) = 4
a - 4 = 4
a = 8
Now, by using the values of a and d, we will find the term for which the value is 0.
a + (n - 1)d = 0
8 + (n - 1)(- 2) = 0
n - 1 = 4
n = 5
Thus, 5th term of the AP will be 0.
☛ Check: NCERT Solutions Class 10 Maths Chapter 5
Video Solution:
If the 3rd and the 9th terms of an AP are 4 and - 8 respectively, which term of this AP is zero?
NCERT Solutions Class 10 Maths Chapter 5 Exercise 5.2 Question 9
Summary:
If the 3rd and the 9th terms of an AP are 4 and - 8 respectively, 5th term of the AP will be zero.
☛ Related Questions:
- 17th term of an AP exceeds its 10th term by 7. Find the common difference.
- Which term of the AP 3,15,27,39... will be 132 more than its 54th term?
- Two APs have the same common difference. The difference between their 100th term is 100, what is the difference between their 1000th terms?
- How many three-digit numbers are divisible by 7?
visual curriculum