If each observation of the data is increased by 5, then their mean
a. remains the same
b. becomes 5 times the original mean
c. is decreased by 5
d. is increased by 5
Solution:
Consider x1, x2, ….. xn as the n observations
Old mean \(\overline{x}_{old}=\frac{\sum_{i=1}^{n}}{n}\) …. (1)
By adding 5 in each observation, new mean becomes
x̄new = (x1 + 5) + (x2 + 5) + …. + (xn + 5)/ n
We can write it as
x̄new = (x1 + x2 + …. + xn) + 5n/ n
So we get
x̄new = \(\frac{\sum_{i=1}^{n}x_{i}}{n}\) + 5 (using equation (1))
x̄new = x̄old + 5
Therefore, their mean has increased by 5.
✦ Try This: If the mean of the observations : x + 5, x + 10, x + 15, x + 20, x + 25 is 10, the mean of the last three observations is
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 14
NCERT Exemplar Class 9 Maths Exercise 14.1 Problem 14
If each observation of the data is increased by 5, then their mean a. remains the same, b. becomes 5 times the original mean, c. is decreased by 5, d. is increased by 5
Summary:
In statistics, the mean for a given set of observations is equal to the sum of all the values of a collection of data divided by the total number of values in the data. If each observation of the data is increased by 5, then their mean is increased by 5
☛ Related Questions:
- Let x̄ be the mean of x1 , x2 , ... , xn and ȳ the mean of y1 , y2 , ... , yn . If z̄ is the mean of . . . .
- If x̄ is the mean of x1 , x2 , ... , xn , then for a ≠ 0, the mean of ax1 , ax2 , ..., axn , x1/a, x . . . .
- If x̄1, x̄2, x̄3, ….., x̄n are the means of n groups with n1 , n2 , ... , nn number of observations . . . .
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