If a number of circles touch a given line segment PQ at a point A, then their centres lie on the perpendicular bisector of PQ. Write ‘True’ or ‘False’ and justify your answer
Solution:
Consider S1, S2, S3, …., Sn be n circles with centers C1, C2, C3, …, Cn.
PQ is a common tangent to all the circles at point A that is common to all circles.
We know that, tangent at any point on the circle is perpendicular to the radius through point of contact
We have,
C1A ⏊ PQ
C2A ⏊ PQ
C3A ⏊ PQ
CnA ⏊ PQ
Here, C1 C2 C3 … Cn lie on the perpendicular line to PQ but not on the perpendicular bisector as PA may or may not be equal to AQ.
Therefore, the statement is false.
✦ Try This: In the diagram, PQ and PS are two straight lines. Which line is the locus of a point such that it is equidistant from lines PQ and PS?
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 10
NCERT Exemplar Class 10 Maths Exercise 9.2 Problem 8
If a number of circles touch a given line segment PQ at a point A, then their centres lie on the perpendicular bisector of PQ. Write ‘True’ or ‘False’ and justify your answer
Summary:
The statement “If a number of circles touch a given line segment PQ at a point A, then their centres lie on the perpendicular bisector of PQ” is false
☛ Related Questions:
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