If 2A7 ÷ A = 33, then find the value of A.
Solution:
When 2A7 is divided by A it gives 33. This also means that when 2A7 is divided by 33 it gives A.
Since 33 = 11 × 3
2A7 is divisible by 3 and 11.
Therefore
A = 2 + 7 = 9
And
2 + 9 + 7 = 18
Which is divisible by 3.
A = 9
✦ Try This: If 9A9B is divisible by 22 what are possible values of A and B.
If 9A9B is divisible by 22 implies that it is divisible by 11 and 2. Therefore,
9A9B is an even number divisible by 11.
Since the number is divisible by 11
9 + 9 - (A + B) = 11
A + B = 7
Which implies that A and can assume the following values:
(a) A = 3, B = 4
(b) A = 4, B = 3
(c) A = 1,B = 6
(d) A = 6, B = 1
(e) A = 5, B = 2
(f) A = 2, B = 5
Since 9A9B is an even number alternatives (b), (d), and (f) are invalid
Therefore the possible values of A and B are,
A = 3, B = 4
A = 1, B = 6
A = 3, B = 4
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 16
NCERT Exemplar Class 8 Maths Chapter 13 Problem 61
If 2A7 ÷ A = 33, then find the value of A.
Summary:
If 2A7 ÷ A = 33, then the value of A is 9.
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