How many numbers lie between squares of the following numbers?
(i) 12 and 13 (ii) 25 and 26 (iii) 99 and 100

Solution:

'2n' numbers lie between the square of two consecutive numbers n and (n+1).

(i)12 and 13

Here, n = 12. Thus, 2n = 2 × 12 = 24 ,

i.e., 24 numbers lie between (12)² and (13)²

(ii) 25 and 26

Here, n = 25 gives 2 × 25 = 50 , i.e., 50 numbers lie between (25)² and (26)²

(iii) 99 and 100

Here, n = 99 gives 2 × 99 = 198, i.e., 198 numbers between (99)² and (100)²

☛ Check: NCERT Solutions for Class 8 Maths Chapter 6

Video Solution:

How many numbers lie between squares of the following numbers? (i) 12 and 13 (ii) 25 and 26 (iii) 99 and 100

NCERT Solutions for Class 8 Maths Chapter 6 Exercise 6.1 Question 9

Summary:

The numbers that lie between the squares of the given questions (i) 12 and 13 (ii) 25 and 26 (iii) 99 and 100 are (i) 24, (ii) 50, (iii) 198

☛ Related Questions:

• The following numbers are obviously not perfect squares. Give reason. (i) 1057 (ii) 23453 (iii) 7928 (iv) 222222 (v) 64000 (vi) 89722 (vii) 222000 (viii) 505050
• The squares of which of the following would be odd numbers? (i) 431 (ii) 2826 (iii) 7779 (iv) 82004
• Observe the following pattern and find the missing digits. 112 = 121 1012 = 10201 10012 = 1002001 1000012 = 1....2....1 100000012 = ...........
• Observe the following pattern and supply the missing numbers. 112 = 121 1012 = 10201 101012 = 102030201 10101012 = ? ?2 = 10203040504030201