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Four friends had a competition to see how far could they hop on one foot. The table given shows the distance covered by each.
Name Distance covered (km)
Seema 1/25
Nancy 1/32
Megha 1/40
Soni 1/20
(a) How farther did Soni hop than Nancy?
(b) What is the total distance covered by Seema and Megha?
(c) Who walked farther, Nancy or Megha?

Solution:

(a) How farther did Soni hop than Nancy?

Subtracting the fractions, we get

Soni distance - Nancy distance = 1/20 - 1/32 = 0.05-0.03=0.02km

(b) What is the total distance covered by Seema and Megha?

Adding fractions, we get

Seema distance + Megha distance = 1/25 + 1/40 = 0.04 + 0.025=0.065km

(c) Who walked farther, Nancy or Megha?

Nancy hopped = 1/32 = 0.03

Megha hopped = 1/40 = 0.025

Nancy hopped farther

✦ Try This: Four friends had a competition to see how far could they hop on one foot. The table given shows the distance covered by each.

Name	Distance covered (km)
Riyan	1/5
Neena	1/3
Saif	1/4
Tina	1/7

(a) How farther did Tina hop than Neena?

(b) What is the total distance covered by Saif and Tina?

(c) Who walked farther, Tina or Neena?

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 1

NCERT Exemplar Class 8 Maths Chapter 1 Problem 144

Four friends had a competition to see how far could they hop on one foot. The table given shows the distance covered by each. Name Distance covered (km) Seema 1/25 Nancy 1/32 Megha 1/40 Soni 1/20. (a) How farther did Soni hop than Nancy, (b) What is the total distance covered by Seema and Megha, (c) Who walked farther, Nancy or Megha

Summary:

Four friends had a competition to see how far could they hop on one foot. The table given shows the distance covered by each. (a) Soni hopped than Nancy by 0.02km, (b) The total distance covered by Seema and Megha is 0.065km, (c) Nancy hopped farther

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