For the polynomial (x³ + 2x + 1)/5 - 7x²/2 - x⁶, write the coefficient of x⁶
Solution:
Given, the polynomial is (x³ + 2x + 1)/5 - 7x²/2 - x⁶
We have to find the coefficient of x⁶.
Rearranging the polynomial,
(x³ + 2x + 1)/5 - 7x²/2 - x⁶ = x³/5 + 2x/5 + 1/5 - 7x²/2 - x⁶
= -x⁶ + x³/5 - 7x²/2 + 2x/5 + 1/5
Therefore, the coefficient of x⁶ = -1
✦ Try This: For the polynomial (2x³ + 4x + 5)/5 - 8x²/3 + 5x⁶, write the coefficient of x²
Given, the polynomial is (2x³ + 4x + 5)/5 - 8x²/3 + 5x⁶
We have to find the coefficient of x².
Rearranging the polynomial,
(2x³ + 4x + 5)/5 - 8x²/3 + 5x⁶ = 2x³/5 + 4x/5 + 5/5 - 8x²/3 + 5x⁶
= 5x⁶ + 2x³/5 - 8x²/3 + 4x/5 + 1
Therefore, the coefficient of x² = -8/3
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2
NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 3(iii)
For the polynomial (x³ + 2x + 1)/5 - 7x²/2 - x⁶, write the coefficient of x⁶
Summary:
Terms that have different variables and different powers are known as unlike terms. For the polynomial (x³ + 2x + 1)/5 - 7x²/2 - x⁶, the coefficient of x⁶ is -1
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