For the polynomial (x³ + 2x + 1)/5 - 7x²/2 - x⁶, write the coefficient of x³
Solution:
Given, the polynomial is (x³ + 2x + 1)/5 - 7x²/2 - x⁶
We have to find the coefficient of x³.
Rearranging the polynomial,
(x³ + 2x + 1)/5 - 7x²/2 - x⁶ = x³/5 + 2x/5 + 1/5 - 7x²/2 - x⁶
= -x⁶ + x³/5 - 7x²/2 + 2x/5 + 1/5
Therefore, the coefficient of x³ = 1/5
✦ Try This: For the polynomial (2x³ + 4x + 5)/5 - 8x²/3 + 5x⁶, write the coefficient of x³
Given, the polynomial is (2x³ + 4x + 5)/5 - 8x²/3 + 5x⁶
We have to find the coefficient of x³.
Rearranging the polynomial,
(2x³ + 4x + 5)/5 - 8x²/3 + 5x⁶ = 2x³/5 + 4x/5 + 5/5 - 8x²/3 + 5x⁶
= 5x⁶ + 2x³/5 - 8x²/3 + 4x/5 + 1
Therefore, the coefficient of x³ = 2/5
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2
NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 3(ii)
For the polynomial (x³ + 2x + 1)/5 - 7x²/2 - x⁶, write the coefficient of x³
Summary:
The terms of polynomials are defined as the parts of the expression that are separated by the operators "+" or "-". For the polynomial (x³ + 2x + 1)/5 - 7x²/2 - x⁶, the coefficient of x³ is 1/5
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