For the pair of equations λx + 3y = -7; 2x + 6y = 14 to have infinitely many solutions, the value of λ should be 1. Is the statement true?
Solution:
Given, the pair of linear equations is
λx + 3y = -7
2x + 6y = 14
We have to determine if λ is 1 the pair of equations has infinitely many solutions.
We know that,
For a pair of linear equations in two variables be a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0,
If \(\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}\), then
i) the pair of linear equation is dependent and consistent
ii) the graph will be a pair of coincident lines. Each point on the lines will be a solution and so the pair of equations will have infinitely many solutions.
Here, a1 = λ, b1 = 3, c1 = -7
a2 = 2, b2 = 6, c2 = 14
So, a1/a2 = λ/2
b1/b2 = 3/6 = 1/2
c1/c2 = -7/14 = -1/2
Case a) λ/2 = 1/2
λ = 2/2
λ = 1
Case b) λ/2 = -1/2
λ = -2/2
λ = -1
The value of λ is not constant.
Therefore, the pair of equations to have infinitely many solutions the value of λ should not be 1.
ā¦ Try This: For the pair of equations λx + 2y = 7; 2x + 4y = 14 to have infinitely many solutions, the value of λ should be 1. Is the statement true?
ā Also Check: NCERT Solutions for Class 10 Maths Chapter 3
NCERT Exemplar Class 10 Maths Exercise 3.2 Problem 4
For the pair of equations λx + 3y = -7; 2x + 6y = 14 to have infinitely many solutions, the value of λ should be 1. Is the statement true?
Summary:
For the pair of equations λx + 3y = -7; 2x + 6y = 14 to have infinitely many solutions, the value of λ should be 1. The statement is not true.
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