For some integer m, every even integer is of the form
a. m
b. m + 1
c. 2m
d. 2m + 1
Solution:
Even integers are 2, 4, 6,….
We can write it in the form of 2m.
m = integer or m = …, -1, 0, 1, 2, 3, ….
2m = …., -2, 0, 2, 4, 6,….
Therefore, 2m = …., -2, 0, 2, 4, 6,….
✦ Try This: Mark has 30 pencils. He distributed 14 of those among his friends. Will he have an even number of pencils left? How do you know?
Mark distributed 14 pencils out of 30 pencils, so he had 16 left with him.
30 - 14 = 16.
16 is a multiple of 2, thus, it is an even number.
Therefore, he will have an even number of pencils left, that is 16
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 1
NCERT Exemplar Class 10 Maths Exercise 1.1 Problem 1
For some integer m, every even integer is of the form a. m, b. m + 1, c. 2m, d. 2m + 1
Summary:
For some integer m, every even integer is of the form 2m
☛ Related Questions:
- For some integer q, every odd integer is of the form a. q, b. q + 1, c. 2q, d. 2q + 1
- n² – 1 is divisible by 8, if n is a. an integer, b. a natural number, c. an odd integer, d. an even . . . .
- If the HCF of 65 and 117 is expressible in the form 65m – 117, then the value of m is (A) 4, (B) 2, . . . .
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