For rational numbers a/b, c/d and e/f we have (a/b) × (c/d + e/f) = __________ + __________

Solution:

Given expression (a/b) × (c/d + e/f)

Using the distributive property over addition, we multiply a/b with c/d and e/f

We get (a/b × c/d) + (a/b × e/f)

✦ Try This: For rational numbers a/b,c/d and e/f we have (1/4) × (1/2 + 3/2) =__________.

Using the distributive property over addition, we multiply a/b with c/d and e/f

We get (1/4 × 1/2) + (1/4 × 3/2)

= (1/8) + (3/8)

= 4/8

= 1/2

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 1

NCERT Exemplar Class 8 Maths Chapter 1 Problem 37

For rational numbers a/b, c/d and e/f we have (a/b) × (c/d + e/f) = __________ + __________

Summary:

For rational numbers a/b,c/d and e/f we have (a/b) × (c/d + e/f) = (a/b × c/d) + (a/b × e/f)

☛ Related Questions:

• -5/7 is ________ than -3
• There are ________ rational numbers between any two rational numbers
• The rational numbers 1/3 and -1/3 are on the ________ sides of zero on the number line