For all real values of c, the pair of equations x - 2y = 8; 5x - 10y = c have a unique solution. Justify whether it is true or false
Solution:
Given, the pair of linear equations is
x - 2y = 8
5x - 10y = c
We have to find the value of c so that the equations have a unique solution.
For a pair of linear equations in two variables be a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0,
if \(\frac{a_{1}}{a_{2}}\neq \frac{b_{1}}{b_{2}}\), then the graph will be a pair of lines intersecting at a unique point, which is the solution of the pair of equations.
Here, a1 = 1, b1 = -2, c1 = 8
a2 = 5, b2 = -10, c2 = c
So, a1/a2 = 1/5
b1/b2 = -2/-10 = 1/5
c1/c2 = 8/c
1/5 = 1/5 = 8/c
So, 1/5 = 8/c
c = 8(5)
c = 40
At c = 40, \(\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}\), the pair of equations have infinitely many solutions.
Therefore, for all real values of c, the pair of equations x - 2y = 8; 5x - 10y = c does not have a unique solution.
ā¦ Try This: For all real values of c, the pair of equations x + 2y = 8; 4x + 8y = c have a unique solution. Justify whether it is true or false
ā Also Check: NCERT Solutions for Class 10 Maths Chapter 3
NCERT Exemplar Class 10 Maths Exercise 3.2 Problem 5
For all real values of c, the pair of equations x - 2y = 8; 5x - 10y = c have a unique solution. Justify whether it is true or false
Summary:
For all real values of c, the pair of equations x - 2y = 8; 5x - 10y = c have a unique solution. The statement is false
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