Foot of a 10 m long ladder leaning against a vertical wall is 6 m away from the base of the wall. Find the height of the point on the wall where the top of the ladder reaches
Solution:
Given, the length of the ladder is 10 m
The foot of the ladder leaning against a vertical wall is 6 m away from the base of the wall.
We have to find the point on the wall where the top of the ladder reaches.
In the figure,
PR is the ladder = 10 m
RQ is the distance from the base of the wall to the foot of the ladder = 6 m
PQ is the height of the point on the wall where the top of the ladder reaches.
By using Pythagorean theorem,
PR² = PQ² + RQ²
(10)² = PQ² + (6)²
100 = PQ² + 36
PQ² = 100 - 36
PQ² = 64
Taking square root,
PQ = 8 m
Therefore, the height of the point on the wall where the top of the ladder reaches is 8 m.
✦ Try This: Foot of a 15 m long ladder leaning against a vertical wall is 8 m away from the base of the wall. Find the height of the point on the wall where the top of the ladder reaches
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 6
NCERT Exemplar Class 10 Maths Exercise 6.3 Problem 15
Foot of a 10 m long ladder leaning against a vertical wall is 6 m away from the base of the wall. Find the height of the point on the wall where the top of the ladder reaches
Summary:
Foot of a 10 m long ladder leaning against a vertical wall is 6 m away from the base of the wall. The height of the point on the wall where the top of the ladder reaches is 8 m
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