Find the values of the trigonometric functions in Exercises 6 to 10:
6. sin 765°

Solution:

sin 765° = sin (2 × 360° + 45°)

We know that the values of sin x repeat after an interval of 360° or 2 π.

⇒ sin 765° = sin 45°

⇒ sin 765° = 1 / √2 (Using trigonometric table)

NCERT Solutions Class 11 Maths Chapter 3 Exercise 3.2 Question 6

Find the values of the trigonometric functions in Exercises 6 to 10. 6.) sin 765°

Summary:

The value of sin 765° = 1/√2.We know that the values of sin x repeat after an interval of 360° or 2 π.