Find the values of k for each of the following quadratic equations, so that they have two equal roots.
(i) 2x2 + kx + 3 = 0 (ii) kx (x - 2) + 6 = 0
Solution:
If a quadratic equation ax2 + bx + c = 0 has two equal real roots, we know that, discriminant b2 - 4ac = 0
(i) 2x2 + kx + 3 = 0
a = 2, b = k, c = 3
b2 - 4ac = 0
(k)2 - 4(2)(3) = 0
k2 - 24 = 0
k2 = 24
k = √24
k = ± √2 × 2 × 2 × 3
k = ± 2√6
(ii) kx (x - 2) + 6 = 0
kx2 - 2kx + 6 = 0
a = k, b = - 2k, c = 6
b2 - 4ac = 0
(-2k)2 - 4(k)(6) = 0
4k2 - 24k = 0
4k (k - 6) = 0
k = 6 and k = 0
If we consider the value of k as 0, then the equation will no longer be quadratic.
Therefore, k = 6
☛ Check: NCERT Solutions Class 10 Maths Chapter 4
Video Solution:
Find the values of k for each of the following quadratic equations, so that they have two equal roots. (i) 2x² + kx + 3 = 0 (ii) kx (x - 2) + 6 = 0
Class 10 Maths NCERT Solutions Chapter 4 Exercise 4.4 Question 2
Summary:
The values of k for each of the following quadratic equations (i) 2x2 + kx + 3 = 0 (ii) kx (x - 2) + 6 = 0 have two equal roots are (i) ± 2√6 and (ii) k = 6 respectively.
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