Find the value of x, if 10000x = (9982)² - (18)²
Solution:
Given, 10000x = (9982)² - (18)²
The identity a² - b² = (a - b) (a + b) can be used in RHS
Here, a = 9982 and b = 18, we get,
10000x = (9982 - 18) (9982 + 18)
10000x = 9964 × 10000
x = (9964 × 10000) / 10000
x = 9964
✦ Try This: Find the value of x, if 2000 x = (9280)² - (20)²
Given, 2000x =(9280)² - (20)²
The identity a² - b² = (a - b) (a + b) can be used in RHS
Here, a = 9280 and b = 20, we get,
2000x = (9280 - 20)(9280 + 20)
2000x = (9260) ×(9300)
x = (9260 × 9300)/2000
x = 43059
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9
NCERT Exemplar Class 8 Maths Chapter 7 Sample Problem 20
Find the value of x, if 10000x = (9982)² - (18)²
Summary:
The value of x, if 10000x = (9982)² - (18)² is 9964
☛ Related Questions:
- The product of a monomial and a binomial is a (a) monomial (b) binomial (c) trinomial (d) none of th . . . .
- In a polynomial, the exponents of the variables are always (a) integers (b) positive integers (c) no . . . .
- Which of the following is correct? (a) (a – b)² = a² + 2ab – b² (b) (a – b)² = a² – 2ab + b² (c) (a . . . .
Math worksheets and
visual curriculum
visual curriculum