Find the value of the letters
C B A
+ C B A
1 A 3 0
Solution:
If A + A = number ending with 0 means
A = 5 and One carries over
B + B + 1(carry Over) = number ending with 3
Which means
B = 1 or 6
But, if B =1 then there will be no carry over which means
1 + C + C ≠ 1A (i.e.1 + C + C cannot be equal to 1A)
Therefore B = 6
6 + 6 + 1 = 13 (One carries over)
C + C + 1 = 1A (Number ending with digit A = 5)
C = 7
7 + 7 + 1 = 15
Therefore
A = 5; B = 6; C = 7
✦ Try This: Find the value of the letters
C B A
+ C B A
1 A 3 4
Since A + A = number ending with 4 implies
A = 7 or A = 2
If A = 2 then there will no carry over and
B + B ≠ 3 ( b plus B cannot be equal to 3 without carryover)
Therefore A = 7
7 + 7 = 14 (one carries over)
B + B + 1 = number ending with 3 and one carries over
Therefore B can be 1 or 6, with B = 1 there will be no carryover.
Hence B = 6
6 + 6 + 1 =13
Therefore B = 6
C + C + 1 = number ending with A = 7
Therefore C = 8
Hence we have
A = 7; B = 6; and C = 8
8 6 7
+ 8 6 7
1 7 3 4
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 16
NCERT Exemplar Class 8 Maths Chapter 13 Problem 53
Find the value of the letters C B A + C B A = 1 A 3 0
Summary:
If C B A + C B A = 1 A 3 0, then A = 5, B = 6 and C = 7
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