Find the value of the letters
A 0 1 B
+ 1 0 A B
B 1 0 8
Solution:
If B + B = number ending with 8 then
B = 4 or 9
If we choose B = 4
Then B + B = 8 (No carry over)
1 + A = number ending with zero means
A = 9 (with one carry over)
A + 1 + 1 = B
But since A = 9 and B = 4
A + 1 + 1≠ B
We therefore choose B = 9
B + B = 18 (one carries over)
A + 1 + 1 = number ending with zero means
A = 8
8 + 1 + 1 = 10 (number ending with 0 and one carry over)
0 + 0 +1 = 1 (in the hundreds place, there is no carry over)
A + 1 = B
A = 8
Therefore B =9
✦ Try This: Find the value of the letters
A B 5 A
+ A B 6 A
3 7 A 2
If A + A = 2 then A = 1 or A = 6
If A = 6 then A + A = 12 (number ending with 2 and carry over 1)
But 5 + 6 + 1 = 12 that ends in digit 2 which means A = 2 but A is assumed as 6.
Therefore now we assume A = 1
A + A = 1 + 1 = 2
5 + 6 = 11 which has ending digit 1 therefore A = 1( A is assumed as 1 only)
B + B + 1 = Number ending with digit 7 implies B = 8 (one carry over)
A + A + 1 = 3 which is true as we know that A = 1
A = 1, B = 8.
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 16
NCERT Exemplar Class 8 Maths Chapter 13 Problem 55
Find the value of the lettersA 0 1 B + 1 0 A B = B 1 0 8
Summary:
If A 0 1 B + 1 0 A B = B 1 0 8, then A = 8, B = 9
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