Find the value of the following polynomial at a = - 2 and b = 3: a³ + 3a²b + 3ab² + b³

Solution:

The given polynomial is a³ + 3a²b + 3ab² + b³

We have to find the value of the polynomial at a = -2 and b = 3.

a³ = (-2)³ = -8

a² = (-2)² = 4

3a²b = 3(4)(3)

= 3(12)

3a²b = 36

b² = (3)² = 9

3ab² = 3(-2)(9)

= 27(-2)

3ab² = -54

b³ = (3)³ = 27

Now, a³ + 3a²b + 3ab² + b³ = -8 + 36 - 54 + 27

=-8 - 54 + 36 + 27

= -62 + 63

= 1

Therefore, a³ + 3a²b + 3ab² + b³ = 1

✦ Try This: Find the value of the following polynomial at a = -3 and b = 3: a³ + 3a²b + 3ab² + b³

☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 12

NCERT Exemplar Class 7 Maths Chapter 10 Problem 66 (c)

Find the value of the following polynomial at a = - 2 and b = 3: a³ + 3a²b + 3ab² + b³

Summary:

The value of the polynomial a³ + 3a²b + 3ab² + b³ at a = -2 and b = 3 is 1

☛ Related Questions:

• Find the value of the following polynomial at a = - 2 and b = 3: a³ - 3a²b + 3ab² - b³
• Find the value of the following polynomial at a = - 2 and b = 3: (a² + b²)/3
• Find the value of the following polynomial at a = - 2 and b = 3: (a² - b²)/3