Find the value of k where 31 k 2 is divisible by 6.

Solution:

Since 6 = 3 × 2

A number divisible by 6 will be divisible both by 3 and 2.

31k2 ends in digit 2 hence it is divisible by 2

To be divisible by 3 the sum of its digits have to be divisible by 3.

3 + 1 + k + 2 is divisible by 3

6 + k is divisible by 3

k = 0 or 3 or 6 or 9

✦ Try This: Find the value of k where 52k 8 is divisible by 8.

A number is divisible by 8 if the number made by the last three digits are divisible by 8.

The number formed by the last three digits 2k8.for 2k8 to be divisible by 8

k = 4, and 8

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 16

NCERT Exemplar Class 8 Maths Chapter 13 Problem 63

Find the value of k where 31 k 2 is divisible by 6.

Summary:

The value of k where 31 k 2 is divisible by 6 is 0 or 3 or 6 or 9.

☛ Related Questions:

• 1y3y6 is divisible by 11. Find the value of y
• 756 x is a multiple of 11, find the value of x
• A three-digit number 2 a 3 is added to the number 326 to give a three-digit number 5b9 which is divi . . . .