Find the value [4⁻¹ + 3⁻¹ + 6⁻²]⁻¹.

Solution:

Given, the expression is [4⁻¹ + 3⁻¹ + 6⁻²]⁻¹.

We have to find the value of the expression.

Using the law of exponents,

a⁻ⁿ = 1/aⁿ

So, 4⁻¹ = 1/4

Similarly, 3⁻¹ = 1/3

6⁻² = 1/6² = 1/36

Now, 4⁻¹ + 3⁻¹ + 6⁻² = 1/4 + 1/3 + 1/36

= (9 + 12 + 1)/36

= 22/36

= 11/18

Now, [4⁻¹ + 3⁻¹ + 6⁻²]⁻¹ = (11/18)⁻¹

= 18/11

Therefore, the required value is 18/11.

✦ Try This: Find the value [5⁻¹ + 7⁻¹ + 3⁻²]⁻¹.

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 12

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NCERT Exemplar Class 8 Maths Chapter 8 Problem 44

Find the value [4⁻¹ + 3⁻¹ + 6⁻²]⁻¹.

Summary:

The value of [4⁻¹ + 3⁻¹ + 6⁻²]⁻¹ is 18/11.

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☛ Related Questions:

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