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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Find the smallest square number that is divisible by each of the numbers 8, 15 and 20
Solution:
The number that will be perfectly divisible by each of the numbers 8, 15, and 20 will be their LCM.
LCM of 8,15, 20
= 2 × 2 × 2 × 3 × 5
= 120
Here we see that prime factors 2, 3, 5 do not have their respective pairs.
Therefore 120 is not a perfect square.
If 120 is multiplied by 2 × 3 × 5, then the number obtained will be a perfect square.
Therefore, 120 × 2 × 3 × 5 = 3600
Thus, the perfect square number is 3600 which is completely divisible by 8, 15, and 20.
☛ Check: NCERT Solutions for Class 8 Maths Chapter 6
Video Solution:
Find the smallest square number that is divisible by each of the numbers 8, 15 and 20
NCERT Solutions for Class 8 Maths Chapter 6 Exercise 6.3 Question 10
Summary:
The smallest perfect square number that is divisible each by 8, 15 and 20 is 3600
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