Find the smallest square number divisible by each one of the numbers 8, 9 and 10.

Solution:

We have to find the smallest square divisible by 8, 9 and 10.

The least number divisible by 8, 9 and 10 is their LCM.

On finding the LCM of 8, 9 and 10,

Now, LCM of 8, 9 and 10 = 2 × 2 × 2 × 3 × 3 × 5 = 360

We observe that 2 and 5 do not occur in pairs.

So, 360 is not a perfect square.

Now, 360 must be multiplied by 2 × 5 to get a perfect square

= 360 × 5 × 2

= 360 × 10

= 3600

Therefore, 3600 is a perfect square.

✦ Try This: Find the smallest square number divisible by each one of the numbers 6, 8 and 9.

☛ Also Check: NCERT Solutions for Class 8 Maths

NCERT Exemplar Class 8 Maths Chapter 3 Problem 131

Find the smallest square number divisible by each one of the numbers 8, 9 and 10

Summary:

The smallest square number divisible by each one of the numbers 8, 9 and 10 is 3600.

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