Find the product of the following pairs of monomials
(i) 4,7p   (ii ) -4p, 7p   (iii ) -4p, 7pq   (iv) 4p³, -3p (v) 4p, 0

Solution:

Multiplication of two algebraic expressions or variable expressions involves multiplying two expressions that are combined with arithmetic operations such as addition, subtraction, multiplication, division, and contain constants, variables, terms, and coefficients.

The product will be as follows.

(i) 4 × 7 p = 4 × 7 × p = 28 p

(ii) - 4 p × 7 p = - 4 × p × 7 × p = (- 4 × 7 ) × ( p × p) = - 28 p²

(iii) - 4 p × 7 pq = - 4 × p × 7 × p × q = (- 4 × 7 ) × ( p × p × q ) = - 28 p²q

(iv) 4 p³ × (-3 p) = 4 × (- 3) × p × p × p × p = -12 p⁴

(v) 4 p × 0 = 4 × p × 0 = 0

☛ Check: NCERT Solutions for Class 8 Maths Chapter 9

Video Solution:

Find the product of the following pairs of monomials. (i) 4,7 p (ii ) -4p, 7p (iii ) -4p, 7pq (iv) 4p³, -3p (v) 4p, 0

Maths NCERT Solutions Class 8 Chapter 9 Exercise 9.2 Question 1

Summary:

The products of the given pairs of monomials (i) 4,7 p (ii ) -4p, 7p (iii ) -4p, 7pq (iv) 4p³, -3p (v) 4p, 0 are (i) 28p, (ii) -28 p², (iii) - 28 p²q, (iv) -12 p⁴, (v) 0

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