Find the product
(i) (a² ) × (2a²² ) × (4a²⁶)   (ii) (2/3 xy) × (-9/10 x² y²)
(iii) (-10/3 pq³ ) × (6/5 p³q)   (iv) x × x² × x³ × x⁴

Solution:

Multiplication of two algebraic expressions or variable expressions involves multiplying two expressions that are combined with arithmetic operations such as addition, subtraction, multiplication, division, and contain constants, variables, terms, and coefficients.

(i) (a² ) × (2a²² ) × (4a²⁶ ) = 2 × 4 × a² × a²² × a²⁶ = 8a⁵⁰ [According to exponent rules, a^m × aⁿ = a^{m + n}]

(ii) (2/3 xy) × ( -9/10 x² y² ) = (2/3) × (-9/10) × x × y × x² × y² = -3/5 x³ y³ [Since, a^m × aⁿ = a^{m + n}]

(iii) (-10/3 pq³) × (6/5 p³q) = -10/3 × 6/5 × p × q³ × p³ × q = - 4 p⁴q⁴ [Since, a^m × aⁿ = a^{m + n}]

(iv) x × x² × x³ × x⁴ = x¹⁰ [Since, a^m × aⁿ = a^{m + n}]

☛ Check: NCERT Solutions for Class 8 Maths Chapter 9

Video Solution:

Find the product. (i) (a² ) × (2a²² ) × (4a²⁶) (ii) (2/3 xy) × (-9/10 x² y²) (iii) (-10/3 pq³ ) × (6/5 p³q) (iv) x × x² × x³ × x⁴

NCERT Solutions Class 8 Maths Chapter 9 Exercise 9.3 Question 3

Summary:

The product of the following expressions: (i) (a² ) × (2a²² ) × (4a²⁶) (ii) (2/3 xy) × (-9/10 x² y²) (iii) (-10/3 pq³ ) × (6/5 p³q) (iv) x × x² × x³ × x⁴ are: (i) 8a⁵⁰, (ii) -3/5 x³ y³, (iii) - 4 p⁴q⁴, (iv) x¹⁰

☛ Related Questions:

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