Find the points where the graph of the equation 3x + 4y = 12 cuts the x-axis and the y-axis

Solution:

Given, the equation of the line is 3x + 4y = 12

We have to find the points where the graph cuts the x-axis and the y-axis.

To find the graph of the equation 3x + 4y = 12 cuts the x-axis,

Put y = 0

3x + 4(0) = 12

3x = 12

x = 12/3

x = 4

Therefore, the graph cuts the x-axis at the point (4, 0)

To find the graph of the equation 3x + 4y = 12 cuts the y-axis

Put x = 0

3(0) + 4y = 12

4y = 12

y = 12/4

y = 3

Therefore, the graph cuts the y-axis at the point (0, 3)

✦ Try This: Find the points where the graph of the equation 5x + 4y = 20 cuts the x-axis and the y-axis.

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 4

NCERT Exemplar Class 9 Maths Exercise 4.3 Sample Problem 1

Find the points where the graph of the equation 3x + 4y = 12 cuts the x-axis and the y-axis

Summary:

The graph will cut the x-axis at y = 0 and the y-axis at x = 0. The points where the graph of the equation 3x + 4y = 12 cuts the x-axis and the y-axis are (4, 0) and (0, 3)

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