Find the number from each of the following expanded forms:
(a) 8×10⁴ + 6×10³ + 0×10² + 4×10¹ + 5×10⁰
(b) 4×10⁵ + 5×10³ + 3×10² + 2×10⁰  (c) 3×10⁴ + 7×10² + 5×10⁰
(d) 9×10⁵ + 2×10² + 3×10¹

Solution:

Expressing a number means we have to expand the given exponent numbers in powers of 10.

(a) 8 × 10⁴ + 6 × 10³ + 0 × 10² + 4 × 10¹ + 5 × 10⁰

= 8 × 10000 + 6 × 1000 + 0 × 100 + 4 × 10 + 5 × 1

= 80000 + 6000 + 0 + 40 + 5

= 86045

(b) 4 × 10⁵ + 5 × 10³ + 3 × 10² + 2 × 10⁰

= 4 × 100000 + 0 × 10000 + 5 × 1000 + 3 × 100 + 0 × 10 + 2 × 1

= 400000 + 0 + 5000 + 300 + 0 + 2

= 405302

(c) 3 × 10⁴ + 7 × 10² + 5 × 10⁰

= 3 × 10000 + 0 × 1000 + 7 × 100 + 0 × 10 + 5 × 1

= 30000 + 0 + 700 + 0 + 5

= 30705

(d) 9 × 10⁵ + 2 × 10² + 3 × 10¹

= 9 × 100000 + 0 × 10000 + 0 × 1000 + 2 × 100 + 3 × 10 + 0 × 1

= 900000 + 0 + 0 + 200 + 30 + 0

= 900230

☛ Check: NCERT Solutions for Class 7 Maths Chapter 13

Video Solution:

Find the number from each of the following expanded forms: (a) 8×10⁴ + 6×10³ + 0×10² + 4×10¹ + 5×10⁰ (b) 4×10⁵ + 5×10³ + 3×10² + 2×10⁰ (c) 3×10⁴ + 7×10² + 5×10⁰ (d) 9×10⁵ + 2×10² + 3×10¹

Maths NCERT Solutions Class 7 Chapter 13 Exercise 13.3 Question 2

Summary:

The number from each of the following expanded forms (a) 8×10⁴ + 6×10³ + 0×10² + 4×10¹ + 5×10⁰ (b) 4×10⁵ + 5×10³ + 3×10² + 2×10⁰ (c) 3×10⁴ + 7×10² + 5×10⁰ (d) 9×10⁵ + 2×10² + 3×10¹ is: (a) 86045, (b) 405302, (c) 30705 , (d) 900230

☛ Related Questions:

• Express The Following Numbers In Standard Form I 50000000 Ii 7000000 Iii 3186500000 Iv 390878 V 390878 Vi 390878
• Express The Number Appearing In The Following Statements In Standard Form A The Distance Between Earth And Moon Is 384000000 M B Speed Of Light In Vacuum Is 300000000 M S
• Simplify I 252 X 73 83 X 7 Ii 25 X 52 X T8 103 X T4 Iii 35 X105 X 25 57 X 65
• Write The Following Numbers In The Expanded Forms 279404 3006194 2806196 120719 20068