Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers.
(i) 26 and 91 (ii) 510 and 92 (iii) 336 and 54
Solution:
LCM × HCF = Product of the two numbers.
- To find the LCM and HCF of the given pairs of the integers, first, find the prime factors of the given pairs of numbers.
- Then, find the product of the smallest power of each common factor in the numbers. This will be the LCM.
- Then, find the product of the greatest power of each prime factor in the number. This would be the HCF.
- Now, we have to verify LCM × HCF = product of the two numbers.
(i) 26 and 91
Prime factors of 26 = 2 × 13
Prime factors of 91 = 7 × 13
HCF of 26 and 91 = 13
LCM of 26 and 91 = 2 × 7 × 13
= 14 × 13
= 182
Product of these two numbers = 26 × 91
= 2366
LCM × HCF = 182 × 13
= 2366
Thus, the product of two numbers = LCM × HCF
(ii) 510 and 92
Prime factors of 510 = 2 × 3 × 5 × 17
Prime factors of 92 = 2 × 2 × 23
HCF of the two numbers = 2
LCM of the two numbers = 2 × 2 × 3 × 5 × 17 × 23
= 23460
Product of these two numbers = 510 × 92
= 46920
LCM x HCF = 2 × 23460
= 46920
Thus, the product of two numbers = LCM × HCF
(iii) 336 and 54
Prime factors of 336 = 2 × 2 × 2 × 2 × 3 × 7
Prime factors of 54 = 2 × 3 × 3 × 3
HCF of the two numbers = 6
LCM of the two numbers = 2 × 2 × 2 × 2 × 3 × 3 × 3 × 7
= 24 × 33 × 7
= 3024
Product of these two numbers = 336 × 54
= 18144
LCM x HCF = 3024 × 6
= 18144
Thus, the product of two numbers = LCM × HCF
☛ Check: NCERT Solutions for Class 10 Maths Chapter 1
Video Solution:
Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. (i) 26 and 91 (ii) 510 and 92 (iii) 336 and 54
NCERT Solutions Class 10 Maths Chapter 1 Exercise 1.2 Question 2
Summary:
The LCM and HCF of the following pairs of integers i) 26 and 91, ii) 510 and 92 and iii) 336 and 54 are: i) 13 and 182, ii) 2 and 23460, and iii) 6 and 3024 respectively and we have verified that LCM × HCF = product of the two numbers in each case.
☛ Related Questions:
- Find the LCM and HCF of the following integers by applying the prime factorisation method. (i) 12, 15 and 21 (ii) 17, 23 and 29 (iii) 8, 9 and 25
- Given that HCF (306, 657) = 9, find LCM (306, 657).
- Check whether 6n can end with the digit 0 for any natural number n.
- Explain why 7 × 11 × 13 + 13 and 7 × 6 × 5 × 4 × 3 × 2 × 1 + 5 are composite numbers.
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