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A day full of math games & activities. Find one near you.
Find the equation of the hyperbola satisfying the given conditions: Foci (± 5, 0), the transverse axis is of length 8
Solution:
Foci (± 5, 0), the transverse axis is of length 8.
Here,
the foci are on the x-axis.
Therefore,
the equation of the hyperbola is of the form x2/a2 - y2/b2 = 1
Since the foci are (± 5, 0), c = 5
Since the length of the transverse axis is 8,
Then,
⇒ 2a = 8
⇒ a = 4
We know that, c2 = a2 + b2
Hence,
⇒ 42 + b2 = 52
⇒ b2 = 25 -16
⇒ b2 = 9
Thus, the equation of the hyperbola is x2/16 - y2/9 = 1
NCERT Solutions Class 11 Maths Chapter 11 Exercise 11.4 Question 10
Find the equation of the hyperbola satisfying the given conditions: Foci (± 5, 0), the transverse axis is of length 8.
Summary:
The equation of the hyperbola is x2/16 - y2/9 = 1 while the Foci are (± 5, 0), and the transverse axis is of length 8
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