Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse x2/49 + y2/36 = 1
Solution:
The given equation is x2/49 + y2/36 = 1
Here, the denominator of x2/49 is greater than the denominator of y2/36
Therefore, the major axis is along the x-axis, while the minor axis is along the y-axis.
On comparing the given equation with
x2/a2 + y2/b2 = 1
we obtain a = 7 and b = 6
Hence,
c = √a² - b²
= √49 - 36
= √13
Therefore,
The coordinates of the foci are (± √13, 0)
The coordinates of the vertices are (± 7, 0)
Length of major axis = 2a = 14
Length of minor axis = 2b = 12
Eccentricity, e = c/a = √13/7
Length of latus rectum = 2b2/a = (2 × 36)/7 = 72/7
NCERT Solutions Class 11 Maths Chapter 11 Exercise 11.3 Question 5
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse x2/49 + y2/36 = 1
Solution:
The coordinates of the foci and vertices are (± √13, 0), (± 7, 0) respectively. The length of the major axis, minor axis, and latus rectum are 14, 12, 72/7 respectively
visual curriculum