Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse x2/16 + y2/9 = 1
Solution:
The given equation is x2/16 + y2/9 = 1
Here, the denominator of x2/16 is greater than the denominator of y2/ 9
Therefore, the major axis is along the x-axis, while the minor axis is along the y-axis.
On comparing the given equation with x2/a2 + y2/b2 = 1 we obtain a = 4 and b = 3
Hence,
c = √a² - b²
= √16 - 9
= √7
Therefore,
The coordinates of the foci are (± √7, 0)
The coordinates of the vertices are (0, ± 4)
Length of major axis = 2a = 8
Length of minor axis = 2b = 6
Eccentricity, e = c/a = √7/4
Length of latus rectum = 2b2/a = (2 × 9)/4 = 9/2
NCERT Solutions Class 11 Maths Chapter 11 Exercise 11.3 Question 3
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse x2/16 + y2/9 = 1
Summary:
The coordinates of the foci and vertices are (± √7, 0), (0, ± 4) respectively. The length of the major axis, minor axis, and latus rectum are 8, 6, 9/2 respectively
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