Find the area of the shaded portion in figure 4.
Solution:
Area of the shaded portion = Area of Trapezium AEFB - Area of unshaded rectangle - Area of unshaded circle
Area of trapezium AEFB = 1/2 × (sum of parallel sides) × height of trapezium
= 1/2 × (120 + 160) × 100 cm²
= 1/2 × 280 × 100cm²
= 14000 cm²
Area of unshaded rectangle = 40 × 20 = 800 cm²
Area of unshaded circle = πr² = (22/7) × (7)² = 154 cm²
Area of shaded portion = 14000 - 800 - 154 = 13,046 cm²
✦ Try This: Find the area of the shaded region.
Area of the shaded portion = Area of Trapezium AEFB - Area of unshaded rectangle - Area of unshaded circle
Area of trapezium AEFB = 1/2 × (sum of parallel sides) × height of trapezium
= 1/2 × (110 + 150) × 100 cm²
= 1/2 × 260 × 105cm²
= 13650 cm²
Area of unshaded rectangle = 50 × 30 = 1500 cm²
Area of unshaded circle = πr² = (22/7) × (14)² = 616 cm²
Area of shaded portion = 13,650 - 1,500 - 616 = 11,534 cm²
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 11
NCERT Exemplar Class 8 Maths Chapter 11 Problem 81
Find the area of the shaded portion in figure 4.
Summary:
The area of the shaded portion is 13,046 cm²
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