Find the area of the field of the given shape.
Solution:
The area of the field (A) = Area of semicircle 1 + Area of square 2 + Area of the quadrant of the circle 3
The Area of the field (A) = 1/2 × π × (12/2)² + 12 × 12 + (1/4) × π × (6)²
The Area of the Field (A) = 1/2 × π × (6)² + 144 + π/4 × 36
The Area of the Field (A) = π/2 × 36 + 144 + π/4 × 36
The Area of the Field (A) = 144 + 3π/4 × 36
The Area of the Field (A) = 228.86cm²
✦ Try This: Find the area of the given field.
The area of the field (A) = Area of semicircle 1 + Area of square 2 + Area of the quadrant of the circle 3
The Area of the field (A) = 1/2 × π × (14/2)² + 14 × 14 + (1/4) × π × (7)²
The Area of the Field (A) = 1/2 × π × (7)² + 196 + π/4 × 49
The Area of the Field (A) = π/2 × 49 + 196 + π/4 × 49
The Area of the Field (A) = 77 + 196 + 77/2 = 311.50
The Area of the Field (A) = 311.50 cm²
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 11
NCERT Exemplar Class 8 Maths Chapter 11 Problem 84
Find the area of the field of the given shape.
Summary:
The area of the field is 228.86cm²
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