Find the area enclosed in Fig. 9.47

Solution:

The figure represents a rectangle and a triangle

We have to find the area enclosed by the figure.

Area of rectangle = length × breadth

= 13 × 4

= 52 cm²

Area of triangle = 1/2 × base × height

Base = 13 - 8 = 5 cm

Height = 16 - 4 = 12 cm

Area of triangle = 1/2 × 5 × 12

= 5(6)

= 30 cm²

Area enclosed by the figure = area of triangle + area of rectangle

= 30 + 52

= 82 cm²

Therefore, the area enclosed by the figure is 82 cm²

✦ Try This: The perimeter of a rhombus is 100 cm and one diagonal is 10 cm long then the length of the other diagonal is

☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 11

NCERT Exemplar Class 7 Maths Chapter 9 Problem 95

Find the area enclosed in Fig. 9.47

Summary:

The area enclosed by the figure is 82 cm²

☛ Related Questions:

• Find the area enclosed in Fig. 9.48
• Find the area enclosed in Fig. 9.49
• Find the area of the shaded region in Fig 9.50