Find the 12th term from the end of the AP: -2, -4,-6, …,-100

Solution:

It is given that

AP : -2, -4, -6,…., -100

First term (a) = -2,

Common difference (d) = -4 - (-2) = -2

Last term (l) = -100

The nth term of an AP from the end

a_n = l - (n - 1 )d,

where l is the last term

d is the common difference.

So the 12th term from the end,

a₁₂ = -100 - (12 - 1)(-2)

= -100 + (11)(2)

= -100 + 22

= -78

Therefore, the 12th term from the end is -78.

✦ Try This: Find the 10th term from the end of the AP: -4, -8,-12, …,-48

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 5

NCERT Exemplar Class 10 Maths Exercise 5.3 Problem 16

Find the 12th term from the end of the AP: -2, -4,-6, …,-100

Summary:

An arithmetic progression (AP) is a sequence where the differences between every two consecutive terms are the same. The 12th term from the end of the AP: -2, -4,-6, …,-100 is -78

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