Find p(0), p(1), p(-2) for the following polynomial : p(y) = (y + 2) (y - 2)

Solution:

Given, the polynomial is p(y) = (y + 2) (y - 2).

We have to find p(0), p(1) and p(-2).

p(0) = (0 + 2)(0 - 2)

= 2(-2)

p(0) = -4

Therefore, the value of the polynomial at p(0) is -4.

p(1) = (1 + 2)(1 - 2)

= 3(-1)

p(1) = -3

Therefore, the value of the polynomial at p(1) is -3.

p(-2) = (-2 + 2)(-2 - 2)

= 0(-4)

p(-2) = 0

Therefore, the value of the- polynomial at p(-2) is 0.

✦ Try This: Find p(0), p(1), p(-2) for the following polynomial : p(x) = 2x + x² + 6

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2

NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 9(ii)

Find p(0), p(1), p(-2) for the following polynomial : p(y) = (y + 2) (y - 2)

Summary:

For the polynomial p(y) = (y + 2) (y - 2), the values of p(0), p(1) and p(-2) are -4, -3 and 0

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