Find p(0), p(1), p(-2) for the following polynomial : p(x) = 10x - 4x² - 3

Solution:

Given, the polynomial is p(x) = 10x - 4x² - 3.

We have to find p(0), p(1) and p(-2).

p(0) = 10(0) - 4(0)² - 3

= 0 - 3

p(0) = -3

Therefore, the value of the polynomial at p(0) is -3.

p(1) = 10(1) - 4(1)² - 3

= 10 - 4 - 3

= 10 - 7

p(1) = 3

Therefore, the value of the polynomial at p(1) is 3.

p(-2) = 10(-2) - 4(-2)² - 3

= -20 - 4(4) - 3

= -20 - 16 - 3

= -36 - 3

p(-2) = -39

Therefore, the value of the polynomial at p(-2) is -39.

✦ Try This: Find p(0), p(1), p(-2) for the following polynomial : p(x) = 11x + 6x² + 3

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2

NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 9(i)

Find p(0), p(1), p(-2) for the following polynomial : p(x) = 10x - 4x² - 3

Summary:

For the polynomial p(x) = 10x - 4x² - 3, the values of p(0), p(1) and p(-2) are -3, 3 and - 39

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