Find:
(i) 7 ÷ 3.5 (ii) 36 ÷ 0.2 (iii) 3.25 ÷ 0.5
(iv) 30.94 ÷ 0.7 (v) 0.5 ÷ 0.25 (vi) 7.75 ÷ 0.25
(vii) 76.5 ÷ 0.15 (viii) 37.8 ÷ 1.4 (ix) 2.73 ÷ 1.3

Solution:

We use the basic concepts of decimal division to solve the given problems.

(i) 7 ÷ 3.5

= 7 × 1/3.5

= 7 × 10/35

= 70/35

= 2/1

= 2

(ii) 36 ÷ 0.2

= 36 × 1/0.2

= 36 × 10/2

= 360/2

= 180

(iii) 3.25 ÷ 0.5

= 3.25 × 1/0.5

= 3.25 × 10/5

= 3.25 × 2

= 6.5

(iv) 30.94 ÷ 0.7

= 3094/100 × 1/0.7

= 3094/100 × 10/7

= 3094/70

= 44.2

(vi) 0.5 ÷ 0.25

= 5/10 × 1/0.25

= 5/10 × 100/25

= 50/25

= 2

(vii) 76.5 ÷ 0.15

= 76.5 × 1/0.15

= 7650/15

= 510

(viii) 37.8 ÷ 1.4

= 37.8 × 1/1.4

= 378/10 × 10/14

= 378/14

= 27

(ix) 2.73 ÷ 1.3

= 273/100 × 10/13

= 21/10

= 2.1

☛ Check: NCERT Solutions for Class 7 Maths Chapter 2

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Video Solution:

Find: (i) 7 ÷ 3.5 (ii) 36 ÷ 0.2 (iii) 3.25 ÷ 0.5 (iv) 30.94 ÷ 0.7 (v) 0.5 ÷ 0.25 (vi) 7.75 ÷ 0.25 (vii) 76.5 ÷ 0.15 (viii) 37.8 ÷ 1.4 (ix) 2.73 ÷ 1.3

NCERT Solutions Class 7 Maths Chapter 2 Exercise 2.7 Question 5

Summary:

The value of the following: (i) 7 ÷ 3.5 (ii) 36 ÷ 0.2 (iii) 3.25 ÷ 0.5 (iv) 30.94 ÷ 0.7 (v) 0.5 ÷ 0.25 (vi) 7.75 ÷ 0.25 (vii) 76.5 ÷ 0.15 (viii) 37.8 ÷ 1.4 (ix) 2.73 ÷ 1.3 are (i) 2, (ii) 180, (iii) 6.5, (iv) 44.2, (vi) 2, (vii) 510, (viii) 27, (ix) 2.1

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