Find:  (i) 4.8 ÷ 10 (ii) 52.5 ÷ 10 (iii) 0.7 ÷ 10 (iv) 33.1 ÷ 10
(v) 272.23 ÷ 10 (vi) 0.56 ÷ 10 (vii) 3.97 ÷10

Solution:

We use the basic concepts of decimal division to solve the given problems.

i) 4.8 ÷ 10

= 48/10 × 1/10

= 48/100

= 0.48

ii) 52.5 ÷ 10

= 525/10 × 1/10

= 525/100

= 5.25

iii) 0.7 ÷ 10

= 7/10 × 1/10

= 7/100

= 0.07

iv) 33.1 ÷ 10

= 331/10 × 1/10

= 331/100

= 3.31

v) 272.23 ÷ 10

= 27223/100 × 1/10

= 27223/1000

= 27.223

vi) 0.56 ÷ 10

= 56/100 × 1/10

= 56/1000

= 0.056

(vii) 3.97 ÷10

= 397/100 × 1/10

= 397/1000

= 0.397

☛ Check: NCERT Solutions for Class 7 Maths Chapter 2

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Video Solution:

Find: (i) 4.8 ÷ 10 (ii) 52.5 ÷ 10 (iii) 0.7 ÷ 10 (iv) 33.1 ÷ 10 (v) 272.23 ÷ 10 (vi) 0.56 ÷ 10 (vii) 3.97 ÷10

NCERT Solutions Class 7 Maths Chapter 2 Exercise 2.7 Question 2

Summary:

The values of the following: (i) 4.8 ÷ 10 (ii) 52.5 ÷ 10 (iii) 0.7 ÷ 10 (iv) 33.1 ÷ 10 (v) 272.23 ÷ 10 (vi) 0.56 ÷ 10 (vii) 3.97 ÷10 are (i) 0.48, (ii) 5.25, (iii) 0.07, (iv) 3.31, (v) 27.223, (vi) 0.056 and (vii) 0.397 respectively.

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