Find:
(i) 2.5 × 0.3 (ii) 0.1 × 51.7 (iii) 0.2 × 316.8
(iv) 1.3 × 3.1 (v) 0.5 × 0.05 (vi) 11.2 × 0.15 (vii) 1.07 × 0.02
(viii) 10.05 × 1.05 (ix) 101.01 × 0.01 (x) 100.01 × 1.1
Solution:
We will use the concepts of decimals and fractions to solve the given questions.
(i) 2.5 × 0.3
= 25/10 × 3/10
= 25 × 3/100
= 75/100
= 0.75
(ii) 0.1 × 51.7
= 1/10 × 517/10
= 1 × 517/100
= 517/100
= 5.17
(iii) 0.2 × 316.8
= 2/10 × 3168/10
= 2 × 3168/100
= 6336/100
= 63.36
(iv) 1.3 × 3.1
= 13/10 × 31/10
= 13 × 31/100
= 403/100 = 4.03
(v) 0.5 × 0.05
= 5/10 × 5/100
= 5 × 5/1000
= 25/1000
= 0.025
(vi) 11.2 × 0.15
= 112/10 × 15/100
= 112 × 15/1000
= 1680/1000
= 1.68
(vii) 1.07 × 0.02
= 107/100 × 2/100
= 107 × 2/10000
= 214/10000
= 0.0214
(viii) 10.05 × 1.05
= 1005/100 × 105/100
= 1005 × 105/10000
= 105525/10000
= 10.5525
(ix) 101.01 × 0.01
= 10101/100 × 1/100
= 10101 × 1/10000
= 10101/10000
= 1.0101
(x) 100.01 × 1.1
= 10001/100 × 11/10
= 10001 × 11/1000
= 110011/1000
= 110.011
☛ Check: NCERT Solutions for Class 7 Maths Chapter 2
Video Solution:
Find: (i) 2.5 × 0.3 (ii) 0.1 × 51.7 (iii) 0.2 × 316.8 (iv) 1.3 × 3.1 (v) 0.5 × 0.05 (vi) 11.2 × 0.15 (vii) 1.07 × 0.02 (viii) 10.05 × 1.05 (ix) 101.01 × 0.01 (x) 100.01 × 1.1
NCERT Solutions Class 7 Maths Chapter 2 Exercise 2.6 Question 5
Summary:
The value of the following : (i) 2.5 × 0.3 (ii) 0.1 × 51.7 (iii) 0.2 × 316.8 (iv) 1.3 × 3.1 (v) 0.5 × 0.05 (vi) 11.2 × 0.15 (vii) 1.07 × 0.02 (viii) 10.05 × 1.05 (ix) 101.01 × 0.01 (x) 100.01 × 1.1 are (i) 0.75, (ii) 5.17 , (iii) 63.36, (iv) 4.03 , (v) 0.025, (vi) 1.68 , (vii) 0.0214, (viii) 10.5525 , (ix) 1.0101 and (x) 110.011 respectively.
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