Find
(a) (– 7) – 8 – (– 25)
(b) (– 13) + 32 – 8 – 1
(c) (– 7) + (– 8) + (– 90)
(d) 50 – (– 40) – (– 2)

Solution:

We use the concepts of positive and negative integers and addition and subtraction to find the values.

(a) (-7) – 8 – (-25)
= (-7) – 8 + 25
= -15 + 25 = 10

(b) First, let’s add all the positive numbers and all the negative numbers separately
(-13) + 32 – 8 – 1
= 32 - 22
= 10

(c) (- 7) + (- 8) + (- 90)
= – (7 + 8 + 90)
= -105

(d) 50 – (-40) – (-2)
= 50 + 40 + 2
= 92

NCERT Solutions Class 6 Maths Chapter 6 Exercise 6.3 Question 4

Find (a) (– 7) – 8 – (– 25) (b) (– 13) + 32 – 8 – 1 (c) (– 7) + (– 8) + (– 90) (d) 50 – (– 40) – (– 2)

Summary:

Using the concepts of positive and negative integers and addition and subtraction, the values determined are (a) 10, (b) 10, (c) - 105, and (d) 92.

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