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Factorise: y² + 8zx - 2xy - 4yz

Solution:

Factorization of an algebraic expression refers to finding out the factors of the given algebraic expression.

Given, y² + 8zx - 2xy - 4yz

This expression does not have a common factor in all the terms.

Rearranging the terms, we can write it as

y² - 2xy - 4yz + 8zx

= y(y - 2x) - 4z(y - 2x)

= (y - 4z)(y - 2x)

✦ Try This: Factorise: q² - 5pq - 3qr + 15pr

Given, q² - 5pq - 3qr + 15pr

= q( q - 5p) - 3r( q - 5p)

=(q - 5p)(q - 3r)

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 88(xv)

Factorise: y² + 8zx - 2xy - 4yz

Summary:

Factorising y² + 8zx - 2xy - 4yz we get, (y - 4z)(y - 2x)

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