Factorise: x³y² + x²y³ - xy⁴ + xy
Solution:
Factorization of an algebraic expression refers to finding out the factors of the given algebraic expression.
In the given expression x³y² + x²y³ - xy⁴ + xy,
The first term x³y² can be factorised as: x × x × x × y × y
The second term x²y³ can be factorised as: x × x × y × y × y
The third term - xy⁴ can be factorised as: (-1) × x × y × y × y × y and
The fourth term xy can be factorised as : x × y
The common factor of all the terms is xy
Taking out the common factor we get,
x³y² + x²y³ - xy⁴ + xy = xy (x²y + xy² - y³ +1)
✦ Try This: Factorise: p⁴q³ + p³q² - p²q² -pq
Given, p⁴q³ + p³q² - p²q² - pq
= pq [p³q² + p²q - pq - 1]
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9
NCERT Exemplar Class 8 Maths Chapter 7 Problem 88(vi)
Factorise: x³y² + x²y³ - xy⁴ + xy
Summary:
Factorising x³y² + x²y³ - xy⁴ + xy we get, xy (x²y + xy² - y³ +1)
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